Public class TestClass extends java.lang. String strI = "" + javac TestClass.java & javap -c TestClass To answer Grodriguez's comment: ** No, the compiler doesn't optimise out the empty string in this case - look: cat TestClass.java Using Integer.toString () The Integer.toString (int) returns a string representing the specified int passed as method argument. As you saw in the previous section, all the protocol buffer types associated. Internally, the former calls the latter, so Integer.toString () should be preferred. In Protoscope, false and true are aliases for these byte strings. It's slightly less efficient ( sb.append() ends up calling Integer.getChars(), which is what Integer.toString() would've done anyway), but it works. To convert an int value into a String, we can use either String.valueOf () or Integer.toString () method. Java has special support for the + operator when used with strings (see the documentation) which translates the code you posted into: StringBuilder sb = new StringBuilder() Īt compile-time. 6 Answers Sorted by: 1018 There are multiple ways: String.valueOf (number) (my preference) '' + number (I don't know how the compiler handles it, perhaps it is as efficient as the above) Integer. The method generally used to convert String to Integer in Java is parseInt() of the String class. ![]() ![]() We usually do this because we can operate with a wide flexible set of operations over strings. ![]() The concatenation will work, but it is unconventional and could be a bad smell as it suggests the author doesn't know about the two methods above (what else might they not know?). In Java, while operating upon strings, there are times when we need to convert a number represented as a string into an integer type. Normal ways would be Integer.toString(i) or String.valueOf(i).
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